What is 3i\times (-3)i ?

The solution to 3i\times (-3)i is 9

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simplify 3i\times (-3)i

simplify

3 i \cdot (- 3) i

9

Solution steps

3 i (- 3) i

Multiply the numbers:

3 (- 3) = - 9

= - 9 ii

Apply exponent rule:

aa = a^{2}

ii = i^{2}

= - 9 i^{2}

Apply imaginary number rule:

i^{2} = - 1

= - 9 (- 1)

Multiply the numbers:

- 9 (- 1) = 9

= 9

\frac{3 x ^{3}}{2 x}

x^{2} + x - 240

8 a

\frac{14}{3 + 2}