What is (-4)/(x-4)+(x^2-2x)/(2x-8) ?

The solution to (-4)/(x-4)+(x^2-2x)/(2x-8) is (x+2)/2

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simplify (-4)/(x-4)+(x^2-2x)/(2x-8)

simplify

\frac{- 4}{x - 4} + \frac{x ^{2} - 2 x}{2 x - 8}

\frac{x + 2}{2}

Solution steps

\frac{- 4}{x - 4} + \frac{x ^{2} - 2 x}{2 x - 8}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 4}{x - 4} = - \frac{4}{x - 4}

= - \frac{4}{x - 4} + \frac{x ^{2} - 2 x}{2 x - 8}

Join

- \frac{4}{x - 4} + \frac{x ^{2} - 2 x}{2 x - 8} : \frac{x + 2}{2}

= \frac{x + 2}{2}

\frac{1}{2} s + \frac{3}{4} s + \frac{1}{4} s + 4

+ 16 x^{2} - 40 x y + 25 y^{2}

30 \times 7

- 2 x^{2} + 2 x + 12

\frac{7}{18} - \frac{2}{9}

What is (-4)/(x-4)+(x^2-2x)/(2x-8) ?
The solution to (-4)/(x-4)+(x^2-2x)/(2x-8) is (x+2)/2