What are the solutions to the equation s^2-2s-15=0 ?

The solutions to the equation s^2-2s-15=0 are s=5,s=-3

Find the zeros of s^2-2s-15=0

The zeros of s^2-2s-15=0 are s=5,s=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

s^{2} - 2 s - 15 = 0

s = 5, s = - 3

Solution steps

s^{2} - 2 s - 15 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

s_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, s_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

s = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

s = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

s = 5, s = - 3

x^{5} \cdot x^{2}

2 \cdot \frac{5}{8}

8 x^{2} - 16 x + 6 = 0

- 5 x^{2} + 7 x = 2

\frac{- 15}{8}

What are the solutions to the equation s^2-2s-15=0 ?
The solutions to the equation s^2-2s-15=0 are s=5,s=-3
Find the zeros of s^2-2s-15=0
The zeros of s^2-2s-15=0 are s=5,s=-3