What is the derivative of 4x^3+4x^2 ?

The derivative of 4x^3+4x^2 is 12x^2+8x

What is the first derivative of 4x^3+4x^2 ?

The first derivative of 4x^3+4x^2 is 12x^2+8x

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derivative of

4 x^{3} + 4 x^{2}

12 x^{2} + 8 x

Solution steps

\frac{d}{d x} (4 x^{3} + 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

= 12 x^{2} + 8 x

1 0^{2.9}

\frac{1}{3} (q - 6)

254 + 524

x^{2} - 8 x - 65

1 0^{1.4}

What is the derivative of 4x^3+4x^2 ?
The derivative of 4x^3+4x^2 is 12x^2+8x
What is the first derivative of 4x^3+4x^2 ?
The first derivative of 4x^3+4x^2 is 12x^2+8x