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Popular >

expand (2y-1)^3

Solution

expand

(2 y - 1)^{3}

Solution

8 y^{3} - 12 y^{2} + 6 y - 1

Solution steps

(2 y - 1)^{3}

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(2 y - 1)^{3} = (2 y)^{3} - 3 (2 y)^{2} \cdot 1 + 3 \cdot 2 y \cdot 1^{2} - 1^{3}

= (2 y)^{3} - 3 (2 y)^{2} \cdot 1 + 3 \cdot 2 y \cdot 1^{2} - 1^{3}

Simplify

(2 y)^{3} - 3 (2 y)^{2} \cdot 1 + 3 \cdot 2 y \cdot 1^{2} - 1^{3} : 8 y^{3} - 12 y^{2} + 6 y - 1

= 8 y^{3} - 12 y^{2} + 6 y - 1

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Frequently Asked Questions (FAQ)

What is expand (2y-1)^3 ?
The solution to expand (2y-1)^3 is 8y^3-12y^2+6y-1