What is factor x^4+2x^3-3x^2-8x-4 ?

The solution to factor x^4+2x^3-3x^2-8x-4 is (x+1)^2(x+2)(x-2)

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factor x^4+2x^3-3x^2-8x-4

factor

x^{4} + 2 x^{3} - 3 x^{2} - 8 x - 4

(x + 1)^{2} (x + 2) (x - 2)

Solution steps

x^{4} + 2 x^{3} - 3 x^{2} - 8 x - 4

Use the rational root theorem

= (x + 1) \frac{x ^{4} + 2 x ^{3} - 3 x ^{2} - 8 x - 4}{x + 1}

\frac{x ^{4} + 2 x ^{3} - 3 x ^{2} - 8 x - 4}{x + 1} = x^{3} + x^{2} - 4 x - 4

= (x + 1) (x^{3} + x^{2} - 4 x - 4)

Factor

x^{3} + x^{2} - 4 x - 4 : (x + 1) (x + 2) (x - 2)

= (x + 1) (x + 1) (x + 2) (x - 2)

Apply exponent rule:

aa = a^{2}

(x + 1) (x + 1) = (x + 1)^{2}

= (x + 1)^{2} (x + 2) (x - 2)

i^{2} + (- i)^{2}

512 a^{3} - 27

x^{2} - 21 x + 54

b + 4 b - 9 b

\frac{2}{1 ^{3}}

What is factor x^4+2x^3-3x^2-8x-4 ?
The solution to factor x^4+2x^3-3x^2-8x-4 is (x+1)^2(x+2)(x-2)