What are the solutions to the equation 14x^2=-21x ?

The solutions to the equation 14x^2=-21x are x=0,x=-3/2

Find the zeros of 14x^2=-21x

The zeros of 14x^2=-21x are x=0,x=-3/2

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14 x^{2} = - 21 x

x = 0, x = - \frac{3}{2}

Decimal Notation

x = 0, x = - 1.5

Solution steps

14 x^{2} = - 21 x

Move

21 x

to the left side

14 x^{2} + 21 x = 0

Factor

14 x^{2} + 21 x : 7 x (2 x + 3)

7 x (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 3 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{3}{2}

11 + 15 x = - 7 + 13 x

8000 = 8 x - (6.06 x + 15000)

a^{2} + 12 a + 35

3 c (2 c + 3)^{- \frac{1}{4}} - 5 (2 c + 3)^{\frac{3}{4}}

5 x = 12

What are the solutions to the equation 14x^2=-21x ?
The solutions to the equation 14x^2=-21x are x=0,x=-3/2
Find the zeros of 14x^2=-21x
The zeros of 14x^2=-21x are x=0,x=-3/2