What is factor 2x^4+x^3+2x^2-3x-2 ?

The solution to factor 2x^4+x^3+2x^2-3x-2 is (x-1)(2x+1)(x^2+x+2)

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factor 2x^4+x^3+2x^2-3x-2

factor

2 x^{4} + x^{3} + 2 x^{2} - 3 x - 2

(x - 1) (2 x + 1) (x^{2} + x + 2)

Solution steps

2 x^{4} + x^{3} + 2 x^{2} - 3 x - 2

Use the rational root theorem

= (x - 1) \frac{2 x ^{4} + x ^{3} + 2 x ^{2} - 3 x - 2}{x - 1}

\frac{2 x ^{4} + x ^{3} + 2 x ^{2} - 3 x - 2}{x - 1} = 2 x^{3} + 3 x^{2} + 5 x + 2

= (x - 1) (2 x^{3} + 3 x^{2} + 5 x + 2)

Factor

2 x^{3} + 3 x^{2} + 5 x + 2 : (2 x + 1) (x^{2} + x + 2)

= (x - 1) (2 x + 1) (x^{2} + x + 2)

lo g_{10} (4) (\frac{1}{64})

w^{7}

- 9 x - 9

34 3^{2}

70 \times 5

What is factor 2x^4+x^3+2x^2-3x-2 ?
The solution to factor 2x^4+x^3+2x^2-3x-2 is (x-1)(2x+1)(x^2+x+2)