What is (9x^3+9x^2-4x-4)/(3x-2) ?

The solution to (9x^3+9x^2-4x-4)/(3x-2) is (x+1)(3x+2)

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simplify (9x^3+9x^2-4x-4)/(3x-2)

simplify

\frac{9 x ^{3} + 9 x ^{2} - 4 x - 4}{3 x - 2}

(x + 1) (3 x + 2)

Solution steps

\frac{9 x ^{3} + 9 x ^{2} - 4 x - 4}{3 x - 2}

= \frac{( 9 x ^{3} + 9 x ^{2} ) + ( - 4 x - 4 )}{3 x - 2}

Factor out

9 x^{2}

from

9 x^{3} + 9 x^{2} : 9 x^{2} (x + 1)

Factor out

- 4

from

- 4 x - 4 : - 4 (x + 1)

= \frac{9 x ^{2} ( x + 1 ) - 4 ( x + 1 )}{3 x - 2}

Factor out common term

x + 1

= \frac{( x + 1 ) ( 9 x ^{2} - 4 )}{3 x - 2}

Factor

9 x^{2} - 4 : (3 x + 2) (3 x - 2)

= \frac{( x + 1 ) ( 3 x + 2 ) ( 3 x - 2 )}{3 x - 2}

Cancel the common factor:

3 x - 2

= (x + 1) (3 x + 2)

- 2 + \frac{3}{6}

6 \frac{6}{10} \times \frac{8}{12}

\frac{x ^{2} + 6 x - 27}{x ^{2} + 2 x - 63}

lo g_{9} (33)

2 \frac{5}{6} + 1 \frac{1}{3}

What is (9x^3+9x^2-4x-4)/(3x-2) ?
The solution to (9x^3+9x^2-4x-4)/(3x-2) is (x+1)(3x+2)