What is (s+1-i)(s+1+i) ?

The solution to (s+1-i)(s+1+i) is s^2+2s+2

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simplify (s+1-i)(s+1+i)

simplify

(s + 1 - i) (s + 1 + i)

s^{2} + 2 s + 2

Solution steps

(s + 1 - i) (s + 1 + i)

Rewrite

s + 1 - i

in standard complex form:

(s + 1) - i

= ((s + 1) - i) (s + 1 + i)

Apply complex arithmetic rule:

(a + bi) (a - bi) = a^{2} + b^{2}

= (s + 1)^{2} + (- 1)^{2}

Simplify

(s + 1)^{2} + (- 1)^{2} : s^{2} + 2 s + 2

= s^{2} + 2 s + 2

(7 \times 1 0^{- 8}) (5 \times 1 0^{11})

\frac{35}{56}

x y^{5} + x^{4} y^{3}

5.1 \cdot 1 - 5.2 \cdot 0 - 3.2

\frac{1}{4} \div \frac{8}{3}