What is 1/(sqrt(2x^2-5x+2)) ?

The solution to 1/(sqrt(2x^2-5x+2)) is (sqrt(2x^2-5x+2))/(2x^2-5x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 1/(sqrt(2x^2-5x+2))

simplify

\frac{1}{2 x ^{2} - 5 x + 2}

\frac{2 x ^{2} - 5 x + 2}{2 x ^{2} - 5 x + 2}

Solution steps

\frac{1}{2 x ^{2} - 5 x + 2}

Multiply by the conjugate

\frac{2 x ^{2} - 5 x + 2}{2 x ^{2} - 5 x + 2}

= \frac{1 \cdot 2 x ^{2} - 5 x + 2}{2 x ^{2} - 5 x + 2 2 x ^{2} - 5 x + 2}

1 \cdot 2 x^{2} - 5 x + 2 = 2 x^{2} - 5 x + 2

2 x^{2} - 5 x + 2 2 x^{2} - 5 x + 2 = 2 x^{2} - 5 x + 2

= \frac{2 x ^{2} - 5 x + 2}{2 x ^{2} - 5 x + 2}

2 + \frac{4}{9}

56 \cdot 14

(z^{2} + 4 x)^{4}

20 0^{3}

8 \times 1 0^{- 4}

What is 1/(sqrt(2x^2-5x+2)) ?
The solution to 1/(sqrt(2x^2-5x+2)) is (sqrt(2x^2-5x+2))/(2x^2-5x+2)