What is expand (5x^2-3x+2)\times (2x^3-1) ?

The solution to expand (5x^2-3x+2)\times (2x^3-1) is 10x^5-5x^2-6x^4+3x+4x^3-2

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expand (5x^2-3x+2)\times (2x^3-1)

expand

(5 x^{2} - 3 x + 2) \cdot (2 x^{3} - 1)

10 x^{5} - 5 x^{2} - 6 x^{4} + 3 x + 4 x^{3} - 2

Solution steps

(5 x^{2} - 3 x + 2) (2 x^{3} - 1)

Distribute parentheses

= 5 x^{2} \cdot 2 x^{3} + 5 x^{2} (- 1) - 3 x \cdot 2 x^{3} - 3 x (- 1) + 2 \cdot 2 x^{3} + 2 (- 1)

Simplify

5 x^{2} \cdot 2 x^{3} + 5 x^{2} (- 1) - 3 x \cdot 2 x^{3} - 3 x (- 1) + 2 \cdot 2 x^{3} + 2 (- 1) : 10 x^{5} - 5 x^{2} - 6 x^{4} + 3 x + 4 x^{3} - 2

= 10 x^{5} - 5 x^{2} - 6 x^{4} + 3 x + 4 x^{3} - 2

2 x^{3} + 7 x^{2} + 4 x - 4

549

\frac{1}{3} + \frac{1}{6} + \frac{1}{2}

2425

\frac{x ^{2} + 16 x + 64}{x ^{2} + x - 56}

What is expand (5x^2-3x+2)\times (2x^3-1) ?
The solution to expand (5x^2-3x+2)\times (2x^3-1) is 10x^5-5x^2-6x^4+3x+4x^3-2