What is the answer to (x-3)(x+3)=(3(x-1))/2+x^2 ?

The answer to (x-3)(x+3)=(3(x-1))/2+x^2 is x=-5

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(x-3)(x+3)=(3(x-1))/2+x^2

(x - 3) (x + 3) = \frac{3 ( x - 1 )}{2} + x^{2}

x = - 5

Solution steps

(x - 3) (x + 3) = \frac{3 ( x - 1 )}{2} + x^{2}

Multiply both sides by

2

2 (x - 3) (x + 3) = 3 (x - 1) + 2 x^{2}

Expand

(x - 3) (x + 3) : x^{2} - 9

2 (x^{2} - 9) = 3 (x - 1) + 2 x^{2}

Expand

2 (x^{2} - 9) : 2 x^{2} - 18

2 x^{2} - 18 = 3 (x - 1) + 2 x^{2}

Expand

3 (x - 1) : 3 x - 3

2 x^{2} - 18 = 3 x - 3 + 2 x^{2}

Move

18

to the right side

2 x^{2} = 2 x^{2} + 3 x + 15

Subtract

2 x^{2} + 3 x

from both sides

2 x^{2} - (2 x^{2} + 3 x) = 2 x^{2} + 3 x + 15 - (2 x^{2} + 3 x)

Simplify

- 3 x = 15

Divide both sides by

- 3

x = - 5

25 - 30 m + 9 m^{2}

(- 3 + \frac{6 i}{n})^{2}

∣ - 6 x ∣ = 30

x + 1 = 8

8 x^{3} < 27

What is the answer to (x-3)(x+3)=(3(x-1))/2+x^2 ?
The answer to (x-3)(x+3)=(3(x-1))/2+x^2 is x=-5
Solve for x: (x-3)(x+3)=(3(x-1))/2+x^2
The solution is x=-5