What is (x^3+4x^2+3x)/(x^3+3x^2+2x) ?

The solution to (x^3+4x^2+3x)/(x^3+3x^2+2x) is (x+3)/(x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x^3+4x^2+3x)/(x^3+3x^2+2x)

simplify

\frac{x ^{3} + 4 x ^{2} + 3 x}{x ^{3} + 3 x ^{2} + 2 x}

\frac{x + 3}{x + 2}

Solution steps

\frac{x ^{3} + 4 x ^{2} + 3 x}{x ^{3} + 3 x ^{2} + 2 x}

Factor

x^{3} + 4 x^{2} + 3 x : x (x + 1) (x + 3)

= \frac{x ( x + 1 ) ( x + 3 )}{x ^{3} + 3 x ^{2} + 2 x}

Factor

x^{3} + 3 x^{2} + 2 x : x (x + 1) (x + 2)

= \frac{x ( x + 1 ) ( x + 3 )}{x ( x + 1 ) ( x + 2 )}

Cancel the common factor:

x

= \frac{( x + 1 ) ( x + 3 )}{( x + 1 ) ( x + 2 )}

Cancel the common factor:

x + 1

= \frac{x + 3}{x + 2}

\frac{x ^{2} - 7 x + 12}{x ^{2} - 16}

\frac{2 x + 3}{6} - \frac{4 x - 7}{9}

(y^{2})^{\frac{3}{2}}

(x + y)^{3} + y^{3}

- \frac{2}{3} 9

What is (x^3+4x^2+3x)/(x^3+3x^2+2x) ?
The solution to (x^3+4x^2+3x)/(x^3+3x^2+2x) is (x+3)/(x+2)