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Popular >

factor 64t^6+1

Solution

factor

64 t^{6} + 1

Solution

(4 t^{2} + 1) (16 t^{4} - 4 t^{2} + 1)

Solution steps

64 t^{6} + 1

Apply exponent rules

= (4 t^{2})^{3} + 1^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(4 t^{2})^{3} + 1^{3} = (4 t^{2} + 1) (4^{2} t^{4} - 4 t^{2} + 1)

= (4 t^{2} + 1) (4^{2} t^{4} - 4 t^{2} + 1)

4^{2} = 16

= (4 t^{2} + 1) (16 t^{4} - 4 t^{2} + 1)

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Frequently Asked Questions (FAQ)

What is factor 64t^6+1 ?
The solution to factor 64t^6+1 is (4t^2+1)(16t^4-4t^2+1)