What is (9b)/(a-b)*(a^2-ab)/(45b) ?

The solution to (9b)/(a-b)*(a^2-ab)/(45b) is a/5

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simplify (9b)/(a-b)*(a^2-ab)/(45b)

simplify

\frac{9 b}{a - b} \cdot \frac{a ^{2} - ab}{45 b}

\frac{a}{5}

Solution steps

\frac{9 b}{a - b} \cdot \frac{a ^{2} - ab}{45 b}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{9 b ( a ^{2} - ab )}{( a - b ) \cdot 45 b}

Cancel the common factor:

b

= \frac{9 ( a ^{2} - ab )}{( a - b ) \cdot 45}

Factor the number:

45 = 9 \cdot 5

= \frac{9 ( a ^{2} - ab )}{( a - b ) \cdot 9 \cdot 5}

Cancel the common factor:

9

= \frac{a ^{2} - ab}{( a - b ) \cdot 5}

Factor

a^{2} - ba : a (a - b)

= \frac{a ( a - b )}{( a - b ) \cdot 5}

Cancel the common factor:

a - b

= \frac{a}{5}

4 \times 5

(2 x^{2} - 1)^{2}

\frac{3 i}{4 - 3 i}

80 \times 5

What is (9b)/(a-b)*(a^2-ab)/(45b) ?
The solution to (9b)/(a-b)*(a^2-ab)/(45b) is a/5