What is (9-17i)/(1-3i) ?

The solution to (9-17i)/(1-3i) is 6+i

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simplify (9-17i)/(1-3i)

simplify

\frac{9 - 17 i}{1 - 3 i}

6 + i

Solution steps

\frac{9 - 17 i}{1 - 3 i}

Multiply by the conjugate

\frac{1 + 3 i}{1 + 3 i}

= \frac{( 9 - 17 i ) ( 1 + 3 i )}{( 1 - 3 i ) ( 1 + 3 i )}

Simplify

\frac{( 9 - 17 i ) ( 1 + 3 i )}{( 1 - 3 i ) ( 1 + 3 i )} : \frac{60 + 10 i}{10}

= \frac{60 + 10 i}{10}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{60}{10} + \frac{10}{10} i

Simplify

\frac{60}{10} + \frac{10}{10} i : 6 + i

= 6 + i

\frac{2}{x} + \frac{3}{x + 1}

0 \times 5

x 160 x^{4} - 6 x^{3} 90

(x - 0) (x - 2)

10 a - 7 b - 4 a + 5 b - 14 b + 3 b