What is (x^2-16)/(x^2+x-20) ?

The solution to (x^2-16)/(x^2+x-20) is (x+4)/(x+5)

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simplify (x^2-16)/(x^2+x-20)

simplify

\frac{x ^{2} - 16}{x ^{2} + x - 20}

\frac{x + 4}{x + 5}

Solution steps

\frac{x ^{2} - 16}{x ^{2} + x - 20}

Factor

x^{2} - 16 : (x + 4) (x - 4)

= \frac{( x + 4 ) ( x - 4 )}{x ^{2} + x - 20}

Factor

x^{2} + x - 20 : (x - 4) (x + 5)

= \frac{( x + 4 ) ( x - 4 )}{( x - 4 ) ( x + 5 )}

Cancel the common factor:

x - 4

= \frac{x + 4}{x + 5}

- 26 \div 2

- 2 i \cdot (- 2 i)

2 \frac{1}{2} - 1 \frac{1}{3}

\frac{x - 1}{2} - \frac{x + 2}{6}

15 x^{2} - 7 x - 4

What is (x^2-16)/(x^2+x-20) ?
The solution to (x^2-16)/(x^2+x-20) is (x+4)/(x+5)