What is factor n^2+4n-32 ?

The solution to factor n^2+4n-32 is (n-4)(n+8)

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factor n^2+4n-32

factor

n^{2} + 4 n - 32

(n - 4) (n + 8)

Solution steps

n^{2} + 4 n - 32

Break the expression into groups

= (n^{2} - 4 n) + (8 n - 32)

Factor out

n

from

n^{2} - 4 n : n (n - 4)

Factor out

8

from

8 n - 32 : 8 (n - 4)

= n (n - 4) + 8 (n - 4)

Factor out common term

n - 4

= (n - 4) (n + 8)

\frac{6 + 32}{2}

- \frac{1}{( 0 + 1 ) ^{2}}

(2 - \frac{2}{3} x)^{2}

sin (3 t) cos (3 t)

\frac{9}{60}