What is (8-3i)-(6+i) ?

The solution to (8-3i)-(6+i) is 2-4i

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simplify (8-3i)-(6+i)

simplify

(8 - 3 i) - (6 + i)

2 - 4 i

Solution steps

(8 - 3 i) - (6 + i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (8 - 6) + (- 3 - 1) i

Simplify

(8 - 6) + (- 3 - 1) i : 2 - 4 i

= 2 - 4 i

\frac{16 x ^{2}}{16 x ^{3}}

- x^{2} - 8 x

75 \times 5

5 cos^{2} (x) - 5