What is (3x^{-2}y^{-4})^{-1} ?

The solution to (3x^{-2}y^{-4})^{-1} is (x^2y^4)/3

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simplify (3x^{-2}y^{-4})^{-1}

simplify

(3 x^{- 2} y^{- 4})^{- 1}

\frac{x ^{2} y ^{4}}{3}

Solution steps

(3 x^{- 2} y^{- 4})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(3 x^{- 2} y^{- 4})^{- 1} = \frac{1}{3 x ^{- 2} y ^{- 4}}

= \frac{1}{3 x ^{- 2} y ^{- 4}}

Multiply

3 x^{- 2} y^{- 4} : \frac{3}{x ^{2} y ^{4}}

= \frac{1}{\frac{3}{x ^{2} y ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{2} y ^{4}}{3}

\frac{3}{24}

1 \frac{1}{4} \times 3

\frac{100}{20}

54 \cdot 5

What is (3x^{-2}y^{-4})^{-1} ?
The solution to (3x^{-2}y^{-4})^{-1} is (x^2y^4)/3