What is 8(-2i)(-5-4i) ?

The solution to 8(-2i)(-5-4i) is -64+80i

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simplify 8(-2i)(-5-4i)

simplify

8 (- 2 i) (- 5 - 4 i)

- 64 + 80 i

Solution steps

8 (- 2 i) (- 5 - 4 i)

Apply rule:

a (- b) = - ab

8 (- 2 i) = - 8 \cdot 2 i

= - 8 \cdot 2 i (- 5 - 4 i)

Multiply the numbers:

- 8 \cdot 2 = - 16

= - 16 i (- 5 - 4 i)

Apply the distributive law:

a (b - c) = ab - a c

- 16 i (- 5 - 4 i) = - 16 i (- 5) - (- 16 i) \cdot 4 i

= - 16 i (- 5) - (- 16 i) \cdot 4 i

Simplify

- 16 i (- 5) - (- 16 i) \cdot 4 i : 80 i - 64

= 80 i - 64

Rewrite in standard complex form:

- 64 + 80 i

= - 64 + 80 i

(w^{2} + 1)^{8}

4 \times 1 0^{7}

2 x (x)

- 9 + \frac{x}{7} + 4

\frac{1}{2} (x + 1)