What is 5/(\frac{5){x-1}+2} ?

The solution to 5/(\frac{5){x-1}+2} is (5(x-1))/(2x+3)

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simplify 5/(\frac{5){x-1}+2}

simplify

\frac{5}{\frac{5}{x - 1} + 2}

\frac{5 ( x - 1 )}{2 x + 3}

Solution steps

\frac{5}{\frac{5}{x - 1} + 2}

Join

\frac{5}{x - 1} + 2 : \frac{2 x + 3}{x - 1}

= \frac{5}{\frac{2 x + 3}{x - 1}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{5 ( x - 1 )}{2 x + 3}

\frac{x}{x ^{- 3}}

3 (x - 2) (x + 1)

- 1 \div \frac{2}{3}

\frac{x ^{2} - 3 x - 4}{x + 1}

53 + 63

What is 5/(\frac{5){x-1}+2} ?
The solution to 5/(\frac{5){x-1}+2} is (5(x-1))/(2x+3)