What is (20cd)/(28bcd) ?

The solution to (20cd)/(28bcd) is 5/(7b)

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simplify (20cd)/(28bcd)

simplify

\frac{20 c d}{28 b c d}

\frac{5}{7 b}

Solution steps

\frac{20 c d}{28 b c d}

Cancel the common factor:

c

= \frac{20 d}{28 b d}

Cancel the common factor:

d

= \frac{20}{28 b}

Factor the number:

20 = 4 \cdot 5

= \frac{4 \cdot 5}{28 b}

Factor the number:

28 = 4 \cdot 7

= \frac{4 \cdot 5}{4 \cdot 7 b}

Cancel the common factor:

4

= \frac{5}{7 b}

8 = \frac{1}{3} (4) + b

x^{2} + 14 x + 4 = 0

30 = 5 t

\frac{π}{π}

- 7 v^{2} - 25 v - 12