What is (3+2i)-(1-6i) ?

The solution to (3+2i)-(1-6i) is 2+8i

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simplify (3+2i)-(1-6i)

simplify

(3 + 2 i) - (1 - 6 i)

2 + 8 i

Solution steps

(3 + 2 i) - (1 - 6 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (3 - 1) + (2 - (- 6)) i

Simplify

(3 - 1) + (2 - (- 6)) i : 2 + 8 i

= 2 + 8 i

+ 8 x y - 32 x z + 40 x

i \cdot 0

\frac{1}{15} + \frac{1}{5}

18 (4)

- 280