What is factor m^6-729 ?

The solution to factor m^6-729 is (m+3)(m-3)(m^2+9+3m)(m^2+9-3m)

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factor m^6-729

factor

m^{6} - 729

(m + 3) (m - 3) (m^{2} + 9 + 3 m) (m^{2} + 9 - 3 m)

Solution steps

m^{6} - 729

Apply exponent rules

= (m^{2})^{3} - 9^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(m^{2})^{3} - 9^{3} = (m^{2} - 9) (m^{4} + 9 m^{2} + 9^{2})

= (m^{2} - 9) (m^{4} + 9 m^{2} + 9^{2})

Factor

m^{2} - 9 : (m + 3) (m - 3)

= (m + 3) (m - 3) (m^{4} + 9 m^{2} + 9^{2})

Factor

m^{4} + 9 m^{2} + 9^{2} : (m^{2} + 9 + 3 m) (m^{2} + 9 - 3 m)

= (m + 3) (m - 3) (m^{2} + 9 + 3 m) (m^{2} + 9 - 3 m)

49 + 36

120 x - 2 x^{2}

\frac{4 x ^{3} - 16 x}{2 x ^{2} + 2 x - 12}

4 t - 10

49 + 16

What is factor m^6-729 ?
The solution to factor m^6-729 is (m+3)(m-3)(m^2+9+3m)(m^2+9-3m)