What is expand 3(x+4)(x-3) ?

The solution to expand 3(x+4)(x-3) is 3x^2+3x-36

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expand 3(x+4)(x-3)

expand

3 (x + 4) (x - 3)

3 x^{2} + 3 x - 36

Solution steps

3 (x + 4) (x - 3)

Expand

3 (x + 4) (x - 3) : 3 (x^{2} + x - 12)

= 3 (x^{2} + x - 12)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

3 (x^{2} + x - 12) = 3 x^{2} + 3 x + 3 (- 12)

= 3 x^{2} + 3 x + 3 (- 12)

Multiply the numbers:

3 (- 12) = - 36

= 3 x^{2} + 3 x - 36

- \frac{5}{7} \cdot 3

- \frac{3}{2} \times (- \frac{2}{3})

(r - h)^{3}

x^{2} + (- x^{2})

\frac{4}{3} + \frac{4}{15}