What is 1/(3-2x)>= 1/(4-5x) ?

The solution to 1/(3-2x)>= 1/(4-5x) is x<= 1/3 \lor 4/5 <x< 3/2

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1/(3-2x)>= 1/(4-5x)

\frac{1}{3 - 2 x} \geq \frac{1}{4 - 5 x}

x \leq \frac{1}{3} or \frac{4}{5} < x < \frac{3}{2}

Interval Notation

(- \infty, \frac{1}{3}] \cup (\frac{4}{5}, \frac{3}{2})

Decimal Notation

x \leq 0.33333 \dots or 0.8 < x < 1.5

Solution steps

\frac{1}{3 - 2 x} \geq \frac{1}{4 - 5 x}

Rewrite in standard form

\frac{- 3 x + 1}{( - 2 x + 3 ) ( - 5 x + 4 )} \geq 0

Identify the intervals

x \leq \frac{1}{3} or \frac{4}{5} < x < \frac{3}{2}

x = \frac{200 9 ^{2} - 2009}{2009}

∣ x + 9 ∣ > 3

- 5 x^{2} + 6 x - 1 = 0

x - \frac{1}{2} \leq x - \frac{1}{3}

- 8 (w + 1) = 2 (1 - 4 w) - 9

What is 1/(3-2x)>= 1/(4-5x) ?
The solution to 1/(3-2x)>= 1/(4-5x) is x<= 1/3 \lor 4/5 <x< 3/2