What is (x^3-5x^2+2x+8)/(x+1) ?

The solution to (x^3-5x^2+2x+8)/(x+1) is (x-2)(x-4)

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simplify (x^3-5x^2+2x+8)/(x+1)

simplify

\frac{x ^{3} - 5 x ^{2} + 2 x + 8}{x + 1}

(x - 2) (x - 4)

Solution steps

\frac{x ^{3} - 5 x ^{2} + 2 x + 8}{x + 1}

Use the rational root theorem

= \frac{( x + 1 ) \frac{x ^{3} - 5 x ^{2} + 2 x + 8}{x + 1}}{x + 1}

\frac{x ^{3} - 5 x ^{2} + 2 x + 8}{x + 1} = x^{2} - 6 x + 8

= \frac{( x + 1 ) ( x ^{2} - 6 x + 8 )}{x + 1}

Factor

x^{2} - 6 x + 8 : (x - 2) (x - 4)

= \frac{( x + 1 ) ( x - 2 ) ( x - 4 )}{x + 1}

Cancel the common factor:

x + 1

= (x - 2) (x - 4)

(3 h + 2) (5 h + 4)

x^{5} - 6 x^{4} + 9 x^{3}

99 + 344

\frac{33}{49}

27 + 18 - 248

What is (x^3-5x^2+2x+8)/(x+1) ?
The solution to (x^3-5x^2+2x+8)/(x+1) is (x-2)(x-4)