What is factor 3r^2+3r+r^3+1 ?

The solution to factor 3r^2+3r+r^3+1 is (r+1)^3

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factor 3r^2+3r+r^3+1

factor

3 r^{2} + 3 r + r^{3} + 1

(r + 1)^{3}

Solution steps

3 r^{2} + 3 r + r^{3} + 1

Write in the standard form

= r^{3} + 3 r^{2} + 3 r + 1

Apply cube of sum rule:

x^{3} + 3 x^{2} y + 3 x y^{2} + y^{3} = (x + y)^{3}

r^{3} + 3 r^{2} + 3 r + 1 = (r + 1)^{3}

= (r + 1)^{3}

\frac{25 - x ^{2}}{25 + 5 x}

\frac{2 π}{\frac{6}{11}}

(9 - 2 i)^{2}

4 (3.14)

\frac{x ^{3} - 343}{x - 7}