What is (35^{-4.7}\times 7^{5.7})/(5^{-3.7)} ?

The solution to (35^{-4.7}\times 7^{5.7})/(5^{-3.7)} is 7/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (35^{-4.7}\times 7^{5.7})/(5^{-3.7)}

simplify

\frac{3 5 ^{- 4.7} \cdot 7 ^{5.7}}{5 ^{- 3.7}}

\frac{7}{5}

Decimal Notation

1.4

Solution steps

\frac{3 5 ^{- 4.7} \cdot 7 ^{5.7}}{5 ^{- 3.7}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

3 5^{- 4.7} = \frac{1}{3 5 ^{4.7}}

= \frac{\frac{1}{3 5 ^{4.7}} \cdot 7 ^{5.7}}{5 ^{- 3.7}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

5^{- 3.7} = \frac{1}{5 ^{3.7}}

= \frac{\frac{1}{3 5 ^{4.7}} \cdot 7 ^{5.7}}{\frac{1}{5 ^{3.7}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{\frac{1}{3 5 ^{4.7}} \cdot 7 ^{5.7} \cdot 5 ^{3.7}}{1}

Cancel

\frac{\frac{1}{3 5 ^{4.7}} \cdot 7 ^{5.7} \cdot 5 ^{3.7}}{1} : \frac{7}{5}

= \frac{7}{5}

4 r^{4} + r^{2}

lo g_{10} (4) (32)

\frac{3}{11} - \frac{1}{2}

\frac{e ^{i x} - e ^{- i x}}{2 i}

What is (35^{-4.7}\times 7^{5.7})/(5^{-3.7)} ?
The solution to (35^{-4.7}\times 7^{5.7})/(5^{-3.7)} is 7/5