What are the solutions to the equation -7x^2+7x+1=-8 ?

The solutions to the equation -7x^2+7x+1=-8 are x=-(-7+sqrt(301))/(14),x=(7+sqrt(301))/(14)

Find the zeros of -7x^2+7x+1=-8

The zeros of -7x^2+7x+1=-8 are x=-(-7+sqrt(301))/(14),x=(7+sqrt(301))/(14)

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- 7 x^{2} + 7 x + 1 = - 8

x = - \frac{- 7 + 301}{14}, x = \frac{7 + 301}{14}

Decimal Notation

x = - 0.73923 \dots, x = 1.73923 \dots

Solution steps

- 7 x^{2} + 7 x + 1 = - 8

Move

8

to the left side

- 7 x^{2} + 7 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 7 ) \cdot 9}{2 ( - 7 )}

7^{2} - 4 (- 7) \cdot 9 = 301

x_{1, 2} = \frac{- 7 \pm 301}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 7 + 301}{2 ( - 7 )}, x_{2} = \frac{- 7 - 301}{2 ( - 7 )}

x = \frac{- 7 + 301}{2 ( - 7 )} : - \frac{- 7 + 301}{14}

x = \frac{- 7 - 301}{2 ( - 7 )} : \frac{7 + 301}{14}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 301}{14}, x = \frac{7 + 301}{14}

x^{2} - 4 x + 4 - 16 y^{2}

- 7 p - 16 > 82

\frac{3}{\frac{3}{2}}

w^{3} - x^{3}

(\frac{3}{2}) x - 2660 = 0

What are the solutions to the equation -7x^2+7x+1=-8 ?
The solutions to the equation -7x^2+7x+1=-8 are x=-(-7+sqrt(301))/(14),x=(7+sqrt(301))/(14)
Find the zeros of -7x^2+7x+1=-8
The zeros of -7x^2+7x+1=-8 are x=-(-7+sqrt(301))/(14),x=(7+sqrt(301))/(14)