What is (x^4-9x^2+4x+12)/((x+1)) ?

The solution to (x^4-9x^2+4x+12)/((x+1)) is (x-2)^2(x+3)

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simplify (x^4-9x^2+4x+12)/((x+1))

simplify

\frac{x ^{4} - 9 x ^{2} + 4 x + 12}{( x + 1 )}

(x - 2)^{2} (x + 3)

Solution steps

\frac{x ^{4} - 9 x ^{2} + 4 x + 12}{x + 1}

Factor

x^{4} - 9 x^{2} + 4 x + 12 : (x + 1) (x - 2)^{2} (x + 3)

= \frac{( x + 1 ) ( x - 2 ) ^{2} ( x + 3 )}{x + 1}

Cancel the common factor:

x + 1

= (x - 2)^{2} (x + 3)

5 x^{2} + 35

40 \times \frac{1}{4}

- \frac{2}{3} + \frac{25}{36}

25 - 49

6^{2} + (63)^{2}

What is (x^4-9x^2+4x+12)/((x+1)) ?
The solution to (x^4-9x^2+4x+12)/((x+1)) is (x-2)^2(x+3)