What are the solutions to the equation 4=x^2-7 ?

The solutions to the equation 4=x^2-7 are x=sqrt(11),x=-sqrt(11)

Find the zeros of 4=x^2-7

The zeros of 4=x^2-7 are x=sqrt(11),x=-sqrt(11)

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4 = x^{2} - 7

x = 11, x = - 11

Decimal

x = 3.31662 \dots, x = - 3.31662 \dots

Solution steps

4 = x^{2} - 7

Switch sides

x^{2} - 7 = 4

Move

7

to the right side

x^{2} = 11

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 11, x = - 11

- 0.6 (2)^{2} + 4.8 (2)

6 x^{2} + 11 x - 35

\frac{2 x + 5}{6} - \frac{2 x}{3} = - \frac{1}{2}

\frac{x - 6}{7} + 8 = - 1

ln (2 e)

What are the solutions to the equation 4=x^2-7 ?
The solutions to the equation 4=x^2-7 are x=sqrt(11),x=-sqrt(11)
Find the zeros of 4=x^2-7
The zeros of 4=x^2-7 are x=sqrt(11),x=-sqrt(11)