What are the solutions to the equation 2x^2-18x-72=0 ?

The solutions to the equation 2x^2-18x-72=0 are x=12,x=-3

Find the zeros of 2x^2-18x-72=0

The zeros of 2x^2-18x-72=0 are x=12,x=-3

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2 x^{2} - 18 x - 72 = 0

x = 12, x = - 3

Solution steps

2 x^{2} - 18 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 2 ( - 72 )}{2 \cdot 2}

(- 18)^{2} - 4 \cdot 2 (- 72) = 30

x_{1, 2} = \frac{- ( - 18 ) \pm 30}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 30}{2 \cdot 2}, x_{2} = \frac{- ( - 18 ) - 30}{2 \cdot 2}

x = \frac{- ( - 18 ) + 30}{2 \cdot 2} : 12

x = \frac{- ( - 18 ) - 30}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = 12, x = - 3

3 x^{2} + 25 x - 18

\frac{2}{3} - \frac{1}{4} + \frac{1}{12}

3 x + 2 x + 9 = 10 - 14

6 - (- 3)

(x - 1) (2 x - 3) = x

What are the solutions to the equation 2x^2-18x-72=0 ?
The solutions to the equation 2x^2-18x-72=0 are x=12,x=-3
Find the zeros of 2x^2-18x-72=0
The zeros of 2x^2-18x-72=0 are x=12,x=-3