What is (x^2-3x-4)/(x^2+4x+3) ?

The solution to (x^2-3x-4)/(x^2+4x+3) is (x-4)/(x+3)

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simplify (x^2-3x-4)/(x^2+4x+3)

simplify

\frac{x ^{2} - 3 x - 4}{x ^{2} + 4 x + 3}

\frac{x - 4}{x + 3}

Solution steps

\frac{x ^{2} - 3 x - 4}{x ^{2} + 4 x + 3}

Factor

x^{2} - 3 x - 4 : (x + 1) (x - 4)

= \frac{( x + 1 ) ( x - 4 )}{x ^{2} + 4 x + 3}

Factor

x^{2} + 4 x + 3 : (x + 1) (x + 3)

= \frac{( x + 1 ) ( x - 4 )}{( x + 1 ) ( x + 3 )}

Cancel the common factor:

x + 1

= \frac{x - 4}{x + 3}

(t^{2} + 2 t + 1)^{2}

2 (3^{x})

\frac{x ^{- 4}}{x ^{6}}

x^{2} - \frac{1}{2}

What is (x^2-3x-4)/(x^2+4x+3) ?
The solution to (x^2-3x-4)/(x^2+4x+3) is (x-4)/(x+3)