What is (y^4)/8+1/(4y^2) ?

The solution to (y^4)/8+1/(4y^2) is (y^6+2)/(8y^2)

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simplify (y^4)/8+1/(4y^2)

simplify

\frac{y ^{4}}{8} + \frac{1}{4 y ^{2}}

\frac{y ^{6} + 2}{8 y ^{2}}

Solution steps

\frac{y ^{4}}{8} + \frac{1}{4 y ^{2}}

Least Common Multiplier of

8, 4 y^{2} : 8 y^{2}

Adjust Fractions based on the LCM

= \frac{y ^{6}}{8 y ^{2}} + \frac{2}{8 y ^{2}}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{y ^{6} + 2}{8 y ^{2}}

lo g_{10} (9) (3)

lo g_{5} (5^{\frac{1}{3}})

\frac{3}{4} + 8

9 x^{2} + 25 x - 6

(7 - 3 i)^{3}