What are the solutions to the equation x^2+25=6x ?

The solutions to the equation x^2+25=6x are x=3+4i,x=3-4i

Find the zeros of x^2+25=6x

The zeros of x^2+25=6x are x=3+4i,x=3-4i

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x^{2} + 25 = 6 x

x = 3 + 4 i, x = 3 - 4 i

Solution steps

x^{2} + 25 = 6 x

Move

6 x

to the left side

x^{2} + 25 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 25 : 8 i

x_{1, 2} = \frac{- ( - 6 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 8 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 8 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 8 i}{2 \cdot 1} : 3 + 4 i

x = \frac{- ( - 6 ) - 8 i}{2 \cdot 1} : 3 - 4 i

The solutions to the quadratic equation are:

x = 3 + 4 i, x = 3 - 4 i

1 - 4 k < 0

15 - 15 x = (4 x + 1) (x - 1)

- 2 \frac{1}{4} x - 3 + 3 = - 17

∣ x - 9 ∣ < 5

b^{2} - 4 b - 32 = 0

What are the solutions to the equation x^2+25=6x ?
The solutions to the equation x^2+25=6x are x=3+4i,x=3-4i
Find the zeros of x^2+25=6x
The zeros of x^2+25=6x are x=3+4i,x=3-4i