What is (8+2i)/(4-3i) ?

The solution to (8+2i)/(4-3i) is 26/25+32/25 i

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simplify (8+2i)/(4-3i)

simplify

\frac{8 + 2 i}{4 - 3 i}

\frac{26}{25} + \frac{32}{25} i

Solution steps

\frac{8 + 2 i}{4 - 3 i}

Multiply by the conjugate

\frac{4 + 3 i}{4 + 3 i}

= \frac{( 8 + 2 i ) ( 4 + 3 i )}{( 4 - 3 i ) ( 4 + 3 i )}

Simplify

\frac{( 8 + 2 i ) ( 4 + 3 i )}{( 4 - 3 i ) ( 4 + 3 i )} : \frac{26 + 32 i}{25}

= \frac{26 + 32 i}{25}

Rewrite in standard complex form:

\frac{26}{25} + \frac{32}{25} i

= \frac{26}{25} + \frac{32}{25} i

- 4 x^{2} - 6 x + 2

(y^{\frac{1}{2}})^{3}

6 \times (- \frac{1}{3})

lo g_{2} (1500)

\frac{3}{2 x}