What are the solutions to the equation 2x^2+4x=6 ?

The solutions to the equation 2x^2+4x=6 are x=1,x=-3

Find the zeros of 2x^2+4x=6

The zeros of 2x^2+4x=6 are x=1,x=-3

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2 x^{2} + 4 x = 6

x = 1, x = - 3

Solution steps

2 x^{2} + 4 x = 6

Move

6

to the left side

2 x^{2} + 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 6) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 2}, x_{2} = \frac{- 4 - 8}{2 \cdot 2}

x = \frac{- 4 + 8}{2 \cdot 2} : 1

x = \frac{- 4 - 8}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

18 n + 12 = 27 n + 3

12 5^{\frac{- 2}{3}}

2 x^{2} - 4 x \geq 0

\frac{- 8 + - 20}{24}

∣ x - 6 ∣ > 3

What are the solutions to the equation 2x^2+4x=6 ?
The solutions to the equation 2x^2+4x=6 are x=1,x=-3
Find the zeros of 2x^2+4x=6
The zeros of 2x^2+4x=6 are x=1,x=-3