What is (20x^3-10x^2+6x)/(2x+4) ?

The solution to (20x^3-10x^2+6x)/(2x+4) is (x(10x^2-5x+3))/(x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (20x^3-10x^2+6x)/(2x+4)

simplify

\frac{20 x ^{3} - 10 x ^{2} + 6 x}{2 x + 4}

\frac{x ( 10 x ^{2} - 5 x + 3 )}{x + 2}

Solution steps

\frac{20 x ^{3} - 10 x ^{2} + 6 x}{2 x + 4}

Factor

20 x^{3} - 10 x^{2} + 6 x : 2 x (10 x^{2} - 5 x + 3)

= \frac{2 x ( 10 x ^{2} - 5 x + 3 )}{2 x + 4}

Factor

2 x + 4 : 2 (x + 2)

= \frac{2 x ( 10 x ^{2} - 5 x + 3 )}{2 ( x + 2 )}

Cancel the common factor:

2

= \frac{x ( 10 x ^{2} - 5 x + 3 )}{x + 2}

\frac{2}{3} (\frac{3}{2})

\frac{2}{5} \times 6

x y^{3} 9 x^{2} y^{6}

\frac{x ^{6} + x ^{13}}{x ^{- 6} + x ^{- 13}}

- \frac{16}{3} + 6

What is (20x^3-10x^2+6x)/(2x+4) ?
The solution to (20x^3-10x^2+6x)/(2x+4) is (x(10x^2-5x+3))/(x+2)