What are the solutions to the equation x^2-5x=10 ?

The solutions to the equation x^2-5x=10 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2

Find the zeros of x^2-5x=10

The zeros of x^2-5x=10 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2

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x^{2} - 5 x = 10

x = \frac{5 + 65}{2}, x = \frac{5 - 65}{2}

Decimal Notation

x = 6.53112 \dots, x = - 1.53112 \dots

Solution steps

x^{2} - 5 x = 10

Move

10

to the left side

x^{2} - 5 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 10) = 65

x_{1, 2} = \frac{- ( - 5 ) \pm 65}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 65}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 65}{2 \cdot 1}

x = \frac{- ( - 5 ) + 65}{2 \cdot 1} : \frac{5 + 65}{2}

x = \frac{- ( - 5 ) - 65}{2 \cdot 1} : \frac{5 - 65}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 65}{2}, x = \frac{5 - 65}{2}

10 0^{0.5}

\frac{x + 4}{- 5} \geq 20

1 - 9 a^{2} b^{4} c^{6} d^{8}

1 - \frac{1}{3} x > 1

\frac{5}{2 - 3}

What are the solutions to the equation x^2-5x=10 ?
The solutions to the equation x^2-5x=10 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2
Find the zeros of x^2-5x=10
The zeros of x^2-5x=10 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2