What are the solutions to the equation x^2-15x+56=0 ?

The solutions to the equation x^2-15x+56=0 are x=8,x=7

Find the zeros of x^2-15x+56=0

The zeros of x^2-15x+56=0 are x=8,x=7

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x^{2} - 15 x + 56 = 0

x = 8, x = 7

Solution steps

x^{2} - 15 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 56 = 1

x_{1, 2} = \frac{- ( - 15 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 1}{2 \cdot 1}

x = \frac{- ( - 15 ) + 1}{2 \cdot 1} : 8

x = \frac{- ( - 15 ) - 1}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 8, x = 7

- \frac{4}{3} + 5

\frac{1}{2} ln (\frac{11}{12})

- 2 x - 4 < - 12 and 9 - 12 x > - 99

1 - \frac{5}{18}

3 x^{2} + 2 x - 1 = 0

What are the solutions to the equation x^2-15x+56=0 ?
The solutions to the equation x^2-15x+56=0 are x=8,x=7
Find the zeros of x^2-15x+56=0
The zeros of x^2-15x+56=0 are x=8,x=7