What is (3x^4+6x)/(2x^4+x^3+4x+2) ?

The solution to (3x^4+6x)/(2x^4+x^3+4x+2) is (3x)/(2x+1)

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simplify (3x^4+6x)/(2x^4+x^3+4x+2)

simplify

\frac{3 x ^{4} + 6 x}{2 x ^{4} + x ^{3} + 4 x + 2}

\frac{3 x}{2 x + 1}

Solution steps

\frac{3 x ^{4} + 6 x}{2 x ^{4} + x ^{3} + 4 x + 2}

Factor

3 x^{4} + 6 x : 3 x (x^{3} + 2)

= \frac{3 x ( x ^{3} + 2 )}{2 x ^{4} + x ^{3} + 4 x + 2}

Factor

2 x^{4} + x^{3} + 4 x + 2 : (2 x + 1) (x^{3} + 2)

= \frac{3 x ( x ^{3} + 2 )}{( 2 x + 1 ) ( x ^{3} + 2 )}

Cancel the common factor:

x^{3} + 2

= \frac{3 x}{2 x + 1}

(- 2 + 2)^{e}

4 x^{2} - y^{2} - 2 x + y

\frac{2 i}{1 + 7 i}

(5 n + 8)^{2}

z 30 z^{2} 35 z^{3}

What is (3x^4+6x)/(2x^4+x^3+4x+2) ?
The solution to (3x^4+6x)/(2x^4+x^3+4x+2) is (3x)/(2x+1)