What is 1/((\frac{12){x+2})-4} ?

The solution to 1/((\frac{12){x+2})-4} is (x+2)/(-4x+4)

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simplify 1/((\frac{12){x+2})-4}

simplify

\frac{1}{( \frac{12}{x + 2} ) - 4}

\frac{x + 2}{- 4 x + 4}

Solution steps

\frac{1}{( \frac{12}{x + 2} ) - 4}

Apply rule:

(a) = a

(\frac{12}{x + 2}) = \frac{12}{x + 2}

= \frac{1}{\frac{12}{x + 2} - 4}

Join

\frac{12}{x + 2} - 4 : \frac{- 4 x + 4}{x + 2}

= \frac{1}{\frac{- 4 x + 4}{x + 2}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x + 2}{- 4 x + 4}

(- \frac{1}{2})!

\frac{sin ^{2} ( x ) + cos ^{2} ( x )}{cos ^{2} ( x ) - 1}

lo g_{5} (123)

7 + - 121

(x + \frac{1}{x})^{- 1}

What is 1/((\frac{12){x+2})-4} ?
The solution to 1/((\frac{12){x+2})-4} is (x+2)/(-4x+4)