What are the solutions to the equation 2x^2+2=-4x ?

The solutions to the equation 2x^2+2=-4x are x=-1

Find the zeros of 2x^2+2=-4x

The zeros of 2x^2+2=-4x are x=-1

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2 x^{2} + 2 = - 4 x

x = - 1

Solution steps

2 x^{2} + 2 = - 4 x

Move

4 x

to the left side

2 x^{2} + 2 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

4^{2} - 4 \cdot 2 \cdot 2 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 2}

x = \frac{- 4}{2 \cdot 2}

\frac{- 4}{2 \cdot 2} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

x^{2} - 2 x < 15

- 3 x^{2} - 6 x = 0

- 42 \leq 8 r - 10 < 22

2 x - 8 \geq 16

8 \cdot 18

What are the solutions to the equation 2x^2+2=-4x ?
The solutions to the equation 2x^2+2=-4x are x=-1
Find the zeros of 2x^2+2=-4x
The zeros of 2x^2+2=-4x are x=-1