What are the solutions to the equation 4x^2+16=0 ?

The solutions to the equation 4x^2+16=0 are x=2i,x=-2i

Find the zeros of 4x^2+16=0

The zeros of 4x^2+16=0 are x=2i,x=-2i

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4 x^{2} + 16 = 0

x = 2 i, x = - 2 i

Solution steps

4 x^{2} + 16 = 0

Move

16

to the right side

4 x^{2} = - 16

Divide both sides by

4

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

(\frac{3 x}{2})^{2}

\frac{6 b - 5}{8 b} - \frac{3 b - 4}{6 b}

1 \frac{2}{5 \cdot \frac{9}{6}}

\frac{( 8 + i )}{( 2 - 3 i )}

5 ∣ x - 3 ∣ < 0.004

What are the solutions to the equation 4x^2+16=0 ?
The solutions to the equation 4x^2+16=0 are x=2i,x=-2i
Find the zeros of 4x^2+16=0
The zeros of 4x^2+16=0 are x=2i,x=-2i