What is (x+6)(1-x)(x-4)>= 0 ?

The solution to (x+6)(1-x)(x-4)>= 0 is x<=-6\lor 1<= x<= 4

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(x+6)(1-x)(x-4)>= 0

(x + 6) (1 - x) (x - 4) \geq 0

x \leq - 6 or 1 \leq x \leq 4

Interval Notation

(- \infty, - 6] \cup [1, 4]

Solution steps

(x + 6) (1 - x) (x - 4) \geq 0

Identify the intervals

x \leq - 6 or 1 \leq x \leq 4

\frac{5 - x}{2} + \frac{3 x - 1}{3} = 4

- 10 r - 20 = - 20

a^{x} + a^{x + 1}

y, x^{3} + y^{2} - 12 x + 16 y = 28

∣ x ∣ = 2.25

What is (x+6)(1-x)(x-4)>= 0 ?
The solution to (x+6)(1-x)(x-4)>= 0 is x<=-6\lor 1<= x<= 4