What is factor 6x^4+7x^3-4x^2-7x-2 ?

The solution to factor 6x^4+7x^3-4x^2-7x-2 is (x-1)(x+1)(2x+1)(3x+2)

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factor 6x^4+7x^3-4x^2-7x-2

factor

6 x^{4} + 7 x^{3} - 4 x^{2} - 7 x - 2

(x - 1) (x + 1) (2 x + 1) (3 x + 2)

Solution steps

6 x^{4} + 7 x^{3} - 4 x^{2} - 7 x - 2

Use the rational root theorem

= (x - 1) \frac{6 x ^{4} + 7 x ^{3} - 4 x ^{2} - 7 x - 2}{x - 1}

\frac{6 x ^{4} + 7 x ^{3} - 4 x ^{2} - 7 x - 2}{x - 1} = 6 x^{3} + 13 x^{2} + 9 x + 2

= (x - 1) (6 x^{3} + 13 x^{2} + 9 x + 2)

Factor

6 x^{3} + 13 x^{2} + 9 x + 2 : (x + 1) (2 x + 1) (3 x + 2)

= (x - 1) (x + 1) (2 x + 1) (3 x + 2)

6 z^{2} 2 z

x^{2} (1 - 2 x)

- 5 x + 3 (6 + 7 x)

(\frac{4.29}{32}) 18

What is factor 6x^4+7x^3-4x^2-7x-2 ?
The solution to factor 6x^4+7x^3-4x^2-7x-2 is (x-1)(x+1)(2x+1)(3x+2)