What are the solutions to the equation x^2+14x=80 ?

The solutions to the equation x^2+14x=80 are x=-7+sqrt(129),x=-7-sqrt(129)

Find the zeros of x^2+14x=80

The zeros of x^2+14x=80 are x=-7+sqrt(129),x=-7-sqrt(129)

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x^{2} + 14 x = 80

x = - 7 + 129, x = - 7 - 129

Decimal Notation

x = 4.35781 \dots, x = - 18.35781 \dots

Solution steps

x^{2} + 14 x = 80

Move

80

to the left side

x^{2} + 14 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 80 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 80) = 2129

x_{1, 2} = \frac{- 14 \pm 2 129}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 129}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 129}{2 \cdot 1}

x = \frac{- 14 + 2 129}{2 \cdot 1} : - 7 + 129

x = \frac{- 14 - 2 129}{2 \cdot 1} : - 7 - 129

The solutions to the quadratic equation are:

x = - 7 + 129, x = - 7 - 129

x^{3} + 9 x^{2} < 0

8 \cdot 6

y + \frac{1}{2} = \frac{1}{3} y + \frac{1}{8}

y^{2} + 9 y + 8

3 (4 y + 9) = 39

What are the solutions to the equation x^2+14x=80 ?
The solutions to the equation x^2+14x=80 are x=-7+sqrt(129),x=-7-sqrt(129)
Find the zeros of x^2+14x=80
The zeros of x^2+14x=80 are x=-7+sqrt(129),x=-7-sqrt(129)